432B - Football Kit - CodeForces Solution

brute force greedy implementation *1200

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Python Code: 

n = int(input())
x = list()
y = list()

for i in range(n):
    a, b = list(map(int, input().split()))
    x.append(a)
    y.append(b)

ans_home = list()
ans_away = list()
cnt = [0]*(10**6)

for i in range(n):
    cnt[x[i]]+=1

for i in range(n):
    ans_home.append(n-1+cnt[y[i]])
    ans_away.append((2*(n-1))-ans_home[i])
    print(ans_home[i], ans_away[i])

C++ Code: 

#include<bits/stdc++.h>
using namespace std;
#define ll long long

int main(){
    int n,t;
    cin>>n;
    int h[200000]={0},a[n+1],i,p,l,s,d;
    for(i=1;i<=n;i++)
    {
        cin>>p>>a[i];
        h[p]++;
    }
    for(i=1;i<=n;i++)
    {
        s=n-1;
        d=h[a[i]];
        if(a[i]==0)
        d=0;
        cout<<s+d<< " "<<s-d<<endl;
    }
    return 0;
}


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